package com.zhu.solution.stringQuestion;


/*反转字符串
编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。

不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
示例 1：

输入：s = ["h","e","l","l","o"]
输出：["o","l","l","e","h"]
示例 2：

输入：s = ["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]

提示：
1 <= s.length <= 105
s[i] 都是 ASCII 码表中的可打印字符
*
* */

import cn.hutool.core.util.ArrayUtil;

import java.util.Arrays;

/**
 * Created with IntelliJ IDEA.
 *
 * @Author: zhujiabao
 * @Date: 2021/12/14/10:51
 * @Description:
 */
public class StringSolution_1 {

    public static void main(String[] args) {
        char[] s = {'h','e','l','l','o','h','e','l','l','o'};
        new StringSolution_1().reverseString(s);
        System.out.println(Arrays.toString(s));
    }

    public void reverseString(char[] s) {
        int length = s.length;
        if (s == null || length <= 1){
            return;
        }

        char temp ;
        for (int n=0,m=length-1; n<m; n++,m--){
            temp = s[n];
            s[n] = s[m];
            s[m] = temp;
        }

        //直接采用工具类反转
        //ArrayUtil.reverse(s);

    }
}
